Let P(n) be the proposition "kah wee likes balloon hats" for all n E Z+

LHS of P(1)=RHS of P(1)



Assume P(k) is true for some k E z+
We wanna show P(k+1) is true

P(k)=


P(k+1)=



Since P(1) is true and P(k) is true => P(k+1) is true, by perfect logical sense, the proposition P(n) is true for n E Z+.